Base | Representation |
---|---|
bin | 10000011101100010000… |
… | …110100111011000110011 |
3 | 11000010212211022221210001 |
4 | 100131202012213120303 |
5 | 122013220402101321 |
6 | 2223402031450431 |
7 | 144504512620603 |
oct | 20354206473063 |
9 | 4003784287701 |
10 | 1131222300211 |
11 | 3a6826552293 |
12 | 1632a4086a17 |
13 | 8289b471c23 |
14 | 3ca73da8c03 |
15 | 1e65ba6cc91 |
hex | 107621a7633 |
1131222300211 has 2 divisors, whose sum is σ = 1131222300212. Its totient is φ = 1131222300210.
The previous prime is 1131222300203. The next prime is 1131222300227. The reversal of 1131222300211 is 1120032221311.
It is a weak prime.
It is an emirp because it is prime and its reverse (1120032221311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131222300211 - 23 = 1131222300203 is a prime.
It is a super-3 number, since 3×11312223002113 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1131225300211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565611150105 + 565611150106.
It is an arithmetic number, because the mean of its divisors is an integer number (565611150106).
Almost surely, 21131222300211 is an apocalyptic number.
1131222300211 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131222300211 is an equidigital number, since it uses as much as digits as its factorization.
1131222300211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1131222300211 its reverse (1120032221311), we get a palindrome (2251254521522).
The spelling of 1131222300211 in words is "one trillion, one hundred thirty-one billion, two hundred twenty-two million, three hundred thousand, two hundred eleven".
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