Base | Representation |
---|---|
bin | 110100101011010011… |
… | …1101111111110110011 |
3 | 101210222200202212020102 |
4 | 1221112213233332303 |
5 | 3323133314113134 |
6 | 123545005503015 |
7 | 11113164423554 |
oct | 1512647577663 |
9 | 353880685212 |
10 | 113122410419 |
11 | 43a7a719297 |
12 | 19b10571a6b |
13 | a88a370535 |
14 | 5691b7232b |
15 | 2e212bb37e |
hex | 1a569effb3 |
113122410419 has 4 divisors (see below), whose sum is σ = 113201023680. Its totient is φ = 113043797160.
The previous prime is 113122410413. The next prime is 113122410431. The reversal of 113122410419 is 914014221311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113122410419 - 228 = 112853974963 is a prime.
It is a super-2 number, since 2×1131224104192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 113122410391 and 113122410400.
It is not an unprimeable number, because it can be changed into a prime (113122410413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39304472 + ... + 39307349.
It is an arithmetic number, because the mean of its divisors is an integer number (28300255920).
Almost surely, 2113122410419 is an apocalyptic number.
113122410419 is a deficient number, since it is larger than the sum of its proper divisors (78613261).
113122410419 is an equidigital number, since it uses as much as digits as its factorization.
113122410419 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78613260.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 113122410419 in words is "one hundred thirteen billion, one hundred twenty-two million, four hundred ten thousand, four hundred nineteen".
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