Base | Representation |
---|---|
bin | 10000011101100010110… |
… | …100011011111101000001 |
3 | 11000010220122221012212011 |
4 | 100131202310123331001 |
5 | 122013231440441001 |
6 | 2223403141132521 |
7 | 144505016666443 |
oct | 20354264337501 |
9 | 4003818835764 |
10 | 1131234312001 |
11 | 3a6832306992 |
12 | 1632a80ba141 |
13 | 828a0ab93b1 |
14 | 3ca75814493 |
15 | 1e65cb41d51 |
hex | 10762d1bf41 |
1131234312001 has 2 divisors, whose sum is σ = 1131234312002. Its totient is φ = 1131234312000.
The previous prime is 1131234311959. The next prime is 1131234312011. The reversal of 1131234312001 is 1002134321311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 833205665601 + 298028646400 = 912801^2 + 545920^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131234312001 - 215 = 1131234279233 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131234312011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565617156000 + 565617156001.
It is an arithmetic number, because the mean of its divisors is an integer number (565617156001).
Almost surely, 21131234312001 is an apocalyptic number.
It is an amenable number.
1131234312001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131234312001 is an equidigital number, since it uses as much as digits as its factorization.
1131234312001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1131234312001 its reverse (1002134321311), we get a palindrome (2133368633312).
The spelling of 1131234312001 in words is "one trillion, one hundred thirty-one billion, two hundred thirty-four million, three hundred twelve thousand, one".
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