11313013021131 has 8 divisors (see below), whose sum is σ = 15339678672960. Its totient is φ = 7414178025032.

The previous prime is 11313013021099. The next prime is 11313013021157. The reversal of 11313013021131 is 13112031031311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11313013021131 - 2⁵ = 11313013021099 is a prime.

It is a super-2 number, since 2×11313013021131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11313013021098 and 11313013021107.

It is not an unprimeable number, because it can be changed into a prime (11313013026131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31957663725 + ... + 31957664078.

It is an arithmetic number, because the mean of its divisors is an integer number (1917459834120).

Almost surely, 2^{11313013021131} is an apocalyptic number.

11313013021131 is a deficient number, since it is larger than the sum of its proper divisors (4026665651829).

11313013021131 is an equidigital number, since it uses as much as digits as its factorization.

11313013021131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63915327865.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 11313013021131 its reverse (13112031031311), we get a palindrome (24425044052442).

The spelling of 11313013021131 in words is "eleven trillion, three hundred thirteen billion, thirteen million, twenty-one thousand, one hundred thirty-one".