Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01110000101000001 |
3 | 1002012102102121102121 |
4 | 22202103232011001 |
5 | 141132112404212 |
6 | 5110325044241 |
7 | 550230011233 |
oct | 124223560501 |
9 | 32172377377 |
10 | 11313013057 |
11 | 48859a0175 |
12 | 2238856681 |
13 | 10b3a30588 |
14 | 7946b0253 |
15 | 4632bdd07 |
hex | 2a24ee141 |
11313013057 has 2 divisors, whose sum is σ = 11313013058. Its totient is φ = 11313013056.
The previous prime is 11313013009. The next prime is 11313013067. The reversal of 11313013057 is 75031031311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11001702321 + 311310736 = 104889^2 + 17644^2 .
It is an emirp because it is prime and its reverse (75031031311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11313013057 is a prime.
It is not a weakly prime, because it can be changed into another prime (11313013067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656506528 + 5656506529.
It is an arithmetic number, because the mean of its divisors is an integer number (5656506529).
Almost surely, 211313013057 is an apocalyptic number.
It is an amenable number.
11313013057 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313013057 is an equidigital number, since it uses as much as digits as its factorization.
11313013057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 945, while the sum is 25.
Adding to 11313013057 its reverse (75031031311), we get a palindrome (86344044368).
The spelling of 11313013057 in words is "eleven billion, three hundred thirteen million, thirteen thousand, fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •