Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01110001011000000 |
3 | 1002012102102121221210 |
4 | 22202103232023000 |
5 | 141132112412230 |
6 | 5110325050120 |
7 | 550230012321 |
oct | 124223561300 |
9 | 32172377853 |
10 | 11313013440 |
11 | 48859a0493 |
12 | 2238856940 |
13 | 10b3a307c1 |
14 | 7946b0448 |
15 | 4632bdeb0 |
hex | 2a24ee2c0 |
11313013440 has 224 divisors, whose sum is σ = 38833470720. Its totient is φ = 2780614656.
The previous prime is 11313013433. The next prime is 11313013447. The reversal of 11313013440 is 4431031311.
It is an interprime number because it is at equal distance from previous prime (11313013433) and next prime (11313013447).
It is not an unprimeable number, because it can be changed into a prime (11313013447) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 666499 + ... + 683261.
Almost surely, 211313013440 is an apocalyptic number.
11313013440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11313013440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19416735360).
11313013440 is an abundant number, since it is smaller than the sum of its proper divisors (27520457280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313013440 is a wasteful number, since it uses less digits than its factorization.
11313013440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16839 (or 16829 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11313013440 its reverse (4431031311), we get a palindrome (15744044751).
The spelling of 11313013440 in words is "eleven billion, three hundred thirteen million, thirteen thousand, four hundred forty".
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