113130401243031 has 16 divisors (see below), whose sum is σ = 167600929216000. Its totient is φ = 75420116843544.

The previous prime is 113130401242993. The next prime is 113130401243039. The reversal of 113130401243031 is 130342104031311.

113130401243031 is a `hidden beast` number, since 1 + 1 + 3 + 13 + 0 + 401 + 243 + 0 + 3 + 1 = 666.

It is not a de Polignac number, because 113130401243031 - 2²¹ = 113130399145879 is a prime.

It is a super-3 number, since 3×113130401243031³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113130401242986 and 113130401243004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113130401243039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10522200 + ... + 18356946.

It is an arithmetic number, because the mean of its divisors is an integer number (10475058076000).

Almost surely, 2^{113130401243031} is an apocalyptic number.

113130401243031 is a deficient number, since it is larger than the sum of its proper divisors (54470527972969).

113130401243031 is an equidigital number, since it uses as much as digits as its factorization.

113130401243031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8369555 (or 8369549 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 113130401243031 its reverse (130342104031311), we get a palindrome (243472505274342).

The spelling of 113130401243031 in words is "one hundred thirteen trillion, one hundred thirty billion, four hundred one million, two hundred forty-three thousand, thirty-one".