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11313044231330 = 255889411920913
BaseRepresentation
bin1010010010100000010111…
…1110111001010010100010
31111001111221111121022111102
42210220011332321102202
52440323103310400310
640021050223514402
72245224532223642
oct244500576712242
944044844538442
1011313044231330
1136719205a1286
121328663758a02
13640a7a84012a
142b17a8c78522
151494291058a5
hexa4a05fb94a2

11313044231330 has 16 divisors (see below), whose sum is σ = 20363524793784. Its totient is φ = 4525207653120.

The previous prime is 11313044231327. The next prime is 11313044231351. The reversal of 11313044231330 is 3313244031311.

It can be written as a sum of positive squares in 4 ways, for example, as 9381558562489 + 1931485668841 = 3062933^2 + 1389779^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11313044231293 and 11313044231302.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4928954 + ... + 6849866.

Almost surely, 211313044231330 is an apocalyptic number.

11313044231330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11313044231330 is a deficient number, since it is larger than the sum of its proper divisors (9050480562454).

11313044231330 is a wasteful number, since it uses less digits than its factorization.

11313044231330 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2509861.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 11313044231330 its reverse (3313244031311), we get a palindrome (14626288262641).

The spelling of 11313044231330 in words is "eleven trillion, three hundred thirteen billion, forty-four million, two hundred thirty-one thousand, three hundred thirty".

Divisors: 1 2 5 10 588941 1177882 1920913 2944705 3841826 5889410 9604565 19209130 1131304423133 2262608846266 5656522115665 11313044231330