Base | Representation |
---|---|
bin | 11001101110010001011101… |
… | …110011011001001010001011 |
3 | 112211120012220202122000001021 |
4 | 121232101131303121022023 |
5 | 104312014303124030443 |
6 | 1040335400344133311 |
7 | 32554305643305034 |
oct | 3156213563311213 |
9 | 484505822560037 |
10 | 113131012330123 |
11 | 33057658160667 |
12 | 1083166b167237 |
13 | 4b1829363c398 |
14 | 1dd17da93da8b |
15 | d12be5ad49ed |
hex | 66e45dcd928b |
113131012330123 has 2 divisors, whose sum is σ = 113131012330124. Its totient is φ = 113131012330122.
The previous prime is 113131012330081. The next prime is 113131012330159. The reversal of 113131012330123 is 321033210131311.
It is a strong prime.
It is an emirp because it is prime and its reverse (321033210131311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113131012330123 - 225 = 113130978775691 is a prime.
It is not a weakly prime, because it can be changed into another prime (113131012331123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565506165061 + 56565506165062.
It is an arithmetic number, because the mean of its divisors is an integer number (56565506165062).
Almost surely, 2113131012330123 is an apocalyptic number.
113131012330123 is a deficient number, since it is larger than the sum of its proper divisors (1).
113131012330123 is an equidigital number, since it uses as much as digits as its factorization.
113131012330123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 113131012330123 its reverse (321033210131311), we get a palindrome (434164222461434).
The spelling of 113131012330123 in words is "one hundred thirteen trillion, one hundred thirty-one billion, twelve million, three hundred thirty thousand, one hundred twenty-three".
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