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1131311233313 is a prime number
BaseRepresentation
bin10000011101100111011…
…001110111100100100001
311000011010000200020001122
4100131213121313210201
5122013411133431223
62223414525542025
7144506642551022
oct20354731674441
94004100606048
101131311233313
113a6871775018
12163309a14915
13828b3a0c371
143ca81b18c49
151e6647885c8
hex10767677921

1131311233313 has 2 divisors, whose sum is σ = 1131311233314. Its totient is φ = 1131311233312.

The previous prime is 1131311233271. The next prime is 1131311233379. The reversal of 1131311233313 is 3133321131311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1007148730624 + 124162502689 = 1003568^2 + 352367^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131311233313 - 232 = 1127016266017 is a prime.

It is a super-2 number, since 2×11313112333132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1131311233513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565655616656 + 565655616657.

It is an arithmetic number, because the mean of its divisors is an integer number (565655616657).

Almost surely, 21131311233313 is an apocalyptic number.

It is an amenable number.

1131311233313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131311233313 is an equidigital number, since it uses as much as digits as its factorization.

1131311233313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1458, while the sum is 26.

Adding to 1131311233313 its reverse (3133321131311), we get a palindrome (4264632364624).

The spelling of 1131311233313 in words is "one trillion, one hundred thirty-one billion, three hundred eleven million, two hundred thirty-three thousand, three hundred thirteen".