11313140000993 has 2 divisors, whose sum is σ = 11313140000994. Its totient is φ = 11313140000992.

The previous prime is 11313140000989. The next prime is 11313140001041. The reversal of 11313140000993 is 39900004131311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8591276863744 + 2721863137249 = 2931088^2 + 1649807^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313140000993 - 2² = 11313140000989 is a prime.

It is not a weakly prime, because it can be changed into another prime (11313140000693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656570000496 + 5656570000497.

It is an arithmetic number, because the mean of its divisors is an integer number (5656570000497).

Almost surely, 2^{11313140000993} is an apocalyptic number.

It is an amenable number.

11313140000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313140000993 is an equidigital number, since it uses as much as digits as its factorization.

11313140000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8748, while the sum is 35.

The spelling of 11313140000993 in words is "eleven trillion, three hundred thirteen billion, one hundred forty million, nine hundred ninety-three", and thus it is an aban number.