113131483 has 2 divisors, whose sum is σ = 113131484. Its totient is φ = 113131482.

The previous prime is 113131451. The next prime is 113131489. The reversal of 113131483 is 384131311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113131483 - 2⁵ = 113131451 is a prime.

It is a super-3 number, since 3×113131483³ (a number of 25 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (113131489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56565741 + 56565742.

It is an arithmetic number, because the mean of its divisors is an integer number (56565742).

Almost surely, 2^113131483 is an apocalyptic number.

113131483 is a deficient number, since it is larger than the sum of its proper divisors (1).

113131483 is an equidigital number, since it uses as much as digits as its factorization.

113131483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 864, while the sum is 25.

The square root of 113131483 is about 10636.3284548758. The cubic root of 113131483 is about 483.6462521694.

Adding to 113131483 its reverse (384131311), we get a palindrome (497262794).

The spelling of 113131483 in words is "one hundred thirteen million, one hundred thirty-one thousand, four hundred eighty-three".