11313161401 has 4 divisors (see below), whose sum is σ = 11376363600. Its totient is φ = 11249959204.

The previous prime is 11313161381. The next prime is 11313161407. The reversal of 11313161401 is 10416131311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11313161401 - 2⁵ = 11313161369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11313161407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31600831 + ... + 31601188.

It is an arithmetic number, because the mean of its divisors is an integer number (2844090900).

Almost surely, 2^11313161401 is an apocalyptic number.

It is an amenable number.

11313161401 is a deficient number, since it is larger than the sum of its proper divisors (63202199).

11313161401 is an equidigital number, since it uses as much as digits as its factorization.

11313161401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63202198.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 11313161401 its reverse (10416131311), we get a palindrome (21729292712).

The spelling of 11313161401 in words is "eleven billion, three hundred thirteen million, one hundred sixty-one thousand, four hundred one".