Base | Representation |
---|---|
bin | 10000011101100111111… |
… | …011010011111011110011 |
3 | 11000011010122011122000202 |
4 | 100131213323103323303 |
5 | 122013420410001433 |
6 | 2223415441505415 |
7 | 144510110223416 |
oct | 20354773237363 |
9 | 4004118148022 |
10 | 1131320000243 |
11 | 3a6876712814 |
12 | 16331094226b |
13 | 828b578b8b4 |
14 | 3ca82d5bb7d |
15 | 1e66541aee8 |
hex | 10767ed3ef3 |
1131320000243 has 2 divisors, whose sum is σ = 1131320000244. Its totient is φ = 1131320000242.
The previous prime is 1131320000203. The next prime is 1131320000249. The reversal of 1131320000243 is 3420000231311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131320000243 - 216 = 1131319934707 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131320000249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660000121 + 565660000122.
It is an arithmetic number, because the mean of its divisors is an integer number (565660000122).
Almost surely, 21131320000243 is an apocalyptic number.
1131320000243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131320000243 is an equidigital number, since it uses as much as digits as its factorization.
1131320000243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1131320000243 its reverse (3420000231311), we get a palindrome (4551320231554).
The spelling of 1131320000243 in words is "one trillion, one hundred thirty-one billion, three hundred twenty million, two hundred forty-three", and thus it is an aban number.
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