Base | Representation |
---|---|
bin | 10000011101100111111… |
… | …111001101011011110001 |
3 | 11000011010201002112212202 |
4 | 100131213333031123301 |
5 | 122013421140202233 |
6 | 2223415515432545 |
7 | 144510122011025 |
oct | 20354777153361 |
9 | 4004121075782 |
10 | 1131321022193 |
11 | 3a68772505aa |
12 | 163311155755 |
13 | 828b5a58abb |
14 | 3ca83146385 |
15 | 1e66556dbe8 |
hex | 10767fcd6f1 |
1131321022193 has 2 divisors, whose sum is σ = 1131321022194. Its totient is φ = 1131321022192.
The previous prime is 1131321022189. The next prime is 1131321022253. The reversal of 1131321022193 is 3912201231311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 779206956529 + 352114065664 = 882727^2 + 593392^2 .
It is an emirp because it is prime and its reverse (3912201231311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1131321022193 - 22 = 1131321022189 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131321922193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660511096 + 565660511097.
It is an arithmetic number, because the mean of its divisors is an integer number (565660511097).
Almost surely, 21131321022193 is an apocalyptic number.
It is an amenable number.
1131321022193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131321022193 is an equidigital number, since it uses as much as digits as its factorization.
1131321022193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 29.
The spelling of 1131321022193 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-one million, twenty-two thousand, one hundred ninety-three".
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