1131321403417 has 2 divisors, whose sum is σ = 1131321403418. Its totient is φ = 1131321403416.

The previous prime is 1131321403361. The next prime is 1131321403447. The reversal of 1131321403417 is 7143041231311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 913102558096 + 218218845321 = 955564^2 + 467139^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131321403417 - 2¹⁵ = 1131321370649 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131321403447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660701708 + 565660701709.

It is an arithmetic number, because the mean of its divisors is an integer number (565660701709).

Almost surely, 2^{1131321403417} is an apocalyptic number.

It is an amenable number.

1131321403417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131321403417 is an equidigital number, since it uses as much as digits as its factorization.

1131321403417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 1131321403417 its reverse (7143041231311), we get a palindrome (8274362634728).

The spelling of 1131321403417 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-one million, four hundred three thousand, four hundred seventeen".