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11313214444 = 227404043373
BaseRepresentation
bin10101000100101000…
…11111001111101100
31002012102210211200101
422202110133033230
5141132140330234
65110333240444
7550231510330
oct124224371754
932172724611
1011313214444
114886018504
122238933124
1310b3aa113c
147947237c0
1546330d814
hex2a251f3ec

11313214444 has 12 divisors (see below), whose sum is σ = 22626428944. Its totient is φ = 4848520464.

The previous prime is 11313214421. The next prime is 11313214453. The reversal of 11313214444 is 44441231311.

11313214444 is an admirable number.

It is a Harshad number since it is a multiple of its sum of digits (28), and also a Moran number because the ratio is a prime number: 404043373 = 11313214444 / (1 + 1 + 3 + 1 + 3 + 2 + 1 + 4 + 4 + 4 + 4).

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 202021659 + ... + 202021714.

Almost surely, 211313214444 is an apocalyptic number.

11313214444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

11313214444 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11313214444 is a wasteful number, since it uses less digits than its factorization.

11313214444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 404043384 (or 404043382 counting only the distinct ones).

The product of its digits is 4608, while the sum is 28.

Adding to 11313214444 its reverse (44441231311), we get a palindrome (55754445755).

The spelling of 11313214444 in words is "eleven billion, three hundred thirteen million, two hundred fourteen thousand, four hundred forty-four".

Divisors: 1 2 4 7 14 28 404043373 808086746 1616173492 2828303611 5656607222 11313214444