Base | Representation |
---|---|
bin | 10101000100101001… |
… | …00101110000101011 |
3 | 1002012102212012021210 |
4 | 22202110211300223 |
5 | 141132142204011 |
6 | 5110334004203 |
7 | 550231651203 |
oct | 124224456053 |
9 | 32172765253 |
10 | 11313241131 |
11 | 4886036565 |
12 | 2238946663 |
13 | 10b3ab032a |
14 | 79472d403 |
15 | 4633166a6 |
hex | 2a2525c2b |
11313241131 has 8 divisors (see below), whose sum is σ = 15086990224. Its totient is φ = 7540826400.
The previous prime is 11313241103. The next prime is 11313241169. The reversal of 11313241131 is 13114231311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11313241131 - 233 = 2723306539 is a prime.
It is a super-2 number, since 2×113132411312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11313241098 and 11313241107.
It is not an unprimeable number, because it can be changed into a prime (11313241171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 313636 + ... + 347841.
It is an arithmetic number, because the mean of its divisors is an integer number (1885873778).
Almost surely, 211313241131 is an apocalyptic number.
11313241131 is a deficient number, since it is larger than the sum of its proper divisors (3773749093).
11313241131 is an equidigital number, since it uses as much as digits as its factorization.
11313241131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 667181.
The product of its digits is 216, while the sum is 21.
Adding to 11313241131 its reverse (13114231311), we get a palindrome (24427472442).
The spelling of 11313241131 in words is "eleven billion, three hundred thirteen million, two hundred forty-one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •