1131324241433 has 4 divisors (see below), whose sum is σ = 1131332189568. Its totient is φ = 1131316293300.

The previous prime is 1131324241423. The next prime is 1131324241441. The reversal of 1131324241433 is 3341424231311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1131324241433 - 2⁴ = 1131324241417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131324241433.

It is not an unprimeable number, because it can be changed into a prime (1131324241403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3756593 + ... + 4046558.

It is an arithmetic number, because the mean of its divisors is an integer number (282833047392).

Almost surely, 2^{1131324241433} is an apocalyptic number.

It is an amenable number.

1131324241433 is a deficient number, since it is larger than the sum of its proper divisors (7948135).

1131324241433 is an equidigital number, since it uses as much as digits as its factorization.

1131324241433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7948134.

The product of its digits is 20736, while the sum is 32.

Adding to 1131324241433 its reverse (3341424231311), we get a palindrome (4472748472744).

The spelling of 1131324241433 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-four million, two hundred forty-one thousand, four hundred thirty-three".