11313243323433 has 16 divisors (see below), whose sum is σ = 16926304646400. Its totient is φ = 7467487340400.

The previous prime is 11313243323407. The next prime is 11313243323491. The reversal of 11313243323433 is 33432334231311.

11313243323433 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 324 + 3 + 323 + 4 + 3 + 3 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-11313243323433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11313243323633) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2074299313 + ... + 2074304766.

It is an arithmetic number, because the mean of its divisors is an integer number (1057894040400).

Almost surely, 2^{11313243323433} is an apocalyptic number.

It is an amenable number.

11313243323433 is a deficient number, since it is larger than the sum of its proper divisors (5613061322967).

11313243323433 is a wasteful number, since it uses less digits than its factorization.

11313243323433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4148604189 (or 4148604183 counting only the distinct ones).

The product of its digits is 139968, while the sum is 36.

Adding to 11313243323433 its reverse (33432334231311), we get a palindrome (44745577554744).

The spelling of 11313243323433 in words is "eleven trillion, three hundred thirteen billion, two hundred forty-three million, three hundred twenty-three thousand, four hundred thirty-three".