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11313313311233 is a prime number
BaseRepresentation
bin1010010010100001011000…
…0001010110101000000001
31111001112122020220222201202
42210220112001112220001
52440324131201424413
640021133035110545
72245234310323313
oct244502601265001
944045566828652
1011313313311233
113671a49476a6a
1213287198a2455
13640ac15031cb
142b17d28bd7b3
15149442a57e58
hexa4a16056a01

11313313311233 has 2 divisors, whose sum is σ = 11313313311234. Its totient is φ = 11313313311232.

The previous prime is 11313313311229. The next prime is 11313313311241. The reversal of 11313313311233 is 33211331331311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9934492521409 + 1378820789824 = 3151903^2 + 1174232^2 .

It is a cyclic number.

It is not a de Polignac number, because 11313313311233 - 22 = 11313313311229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313313311196 and 11313313311205.

It is not a weakly prime, because it can be changed into another prime (11313313311203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656656655616 + 5656656655617.

It is an arithmetic number, because the mean of its divisors is an integer number (5656656655617).

Almost surely, 211313313311233 is an apocalyptic number.

It is an amenable number.

11313313311233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313313311233 is an equidigital number, since it uses as much as digits as its factorization.

11313313311233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4374, while the sum is 29.

Adding to 11313313311233 its reverse (33211331331311), we get a palindrome (44524644642544).

The spelling of 11313313311233 in words is "eleven trillion, three hundred thirteen billion, three hundred thirteen million, three hundred eleven thousand, two hundred thirty-three".