11313421400114 has 4 divisors (see below), whose sum is σ = 16970132100174. Its totient is φ = 5656710700056.

The previous prime is 11313421400101. The next prime is 11313421400117. The reversal of 11313421400114 is 41100412431311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11313354242089 + 67158025 = 3363533^2 + 8195^2 .

It is a super-3 number, since 3×11313421400114³ (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (11313421400117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828355350027 + ... + 2828355350030.

Almost surely, 2^{11313421400114} is an apocalyptic number.

11313421400114 is a deficient number, since it is larger than the sum of its proper divisors (5656710700060).

11313421400114 is an equidigital number, since it uses as much as digits as its factorization.

11313421400114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5656710700059.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 11313421400114 its reverse (41100412431311), we get a palindrome (52413833831425).

The spelling of 11313421400114 in words is "eleven trillion, three hundred thirteen billion, four hundred twenty-one million, four hundred thousand, one hundred fourteen".