Base | Representation |
---|---|
bin | 10101000100101011… |
… | …11100001001001001 |
3 | 1002012110112011122022 |
4 | 22202111330021021 |
5 | 141132240014303 |
6 | 5110345334225 |
7 | 550234653563 |
oct | 124225741111 |
9 | 32173464568 |
10 | 11313594953 |
11 | 4886258381 |
12 | 2238a97375 |
13 | 10b3ba53ab |
14 | 7947c2333 |
15 | 463386438 |
hex | 2a257c249 |
11313594953 has 4 divisors (see below), whose sum is σ = 11314848528. Its totient is φ = 11312341380.
The previous prime is 11313594947. The next prime is 11313594967. The reversal of 11313594953 is 35949531311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35949531311 = 239 ⋅150416449.
It is a cyclic number.
It is not a de Polignac number, because 11313594953 - 216 = 11313529417 is a prime.
It is a super-3 number, since 3×113135949533 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313594353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 613151 + ... + 631332.
It is an arithmetic number, because the mean of its divisors is an integer number (2828712132).
Almost surely, 211313594953 is an apocalyptic number.
It is an amenable number.
11313594953 is a deficient number, since it is larger than the sum of its proper divisors (1253575).
11313594953 is an equidigital number, since it uses as much as digits as its factorization.
11313594953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1253574.
The product of its digits is 218700, while the sum is 44.
The spelling of 11313594953 in words is "eleven billion, three hundred thirteen million, five hundred ninety-four thousand, nine hundred fifty-three".
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