1131400537 has 2 divisors, whose sum is σ = 1131400538. Its totient is φ = 1131400536.

The previous prime is 1131400511. The next prime is 1131400553. The reversal of 1131400537 is 7350041311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 798119001 + 333281536 = 28251^2 + 18256^2 .

It is an emirp because it is prime and its reverse (7350041311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1131400537 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131440537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565700268 + 565700269.

It is an arithmetic number, because the mean of its divisors is an integer number (565700269).

Almost surely, 2^1131400537 is an apocalyptic number.

It is an amenable number.

1131400537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131400537 is an equidigital number, since it uses as much as digits as its factorization.

1131400537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 25.

The square root of 1131400537 is about 33636.2979086581. The cubic root of 1131400537 is about 1042.0105758558.

Adding to 1131400537 its reverse (7350041311), we get a palindrome (8481441848).

The spelling of 1131400537 in words is "one billion, one hundred thirty-one million, four hundred thousand, five hundred thirty-seven".