| Base | Representation |
|---|---|
| bin | 10000011101101100110… |
| … | …100101001111000010000 |
| 3 | 11000011100100201211020102 |
| 4 | 100131230310221320100 |
| 5 | 122014102422004300 |
| 6 | 2223431534231532 |
| 7 | 144512125344422 |
| oct | 20355464517020 |
| 9 | 4004310654212 |
| 10 | 1131402141200 |
| 11 | 3a6909016501 |
| 12 | 1633343555a8 |
| 13 | 828c97bb606 |
| 14 | 3ca8dc20812 |
| 15 | 1e66c7440d5 |
| hex | 1076cd29e10 |
1131402141200 has 180 divisors, whose sum is σ = 2756545865532. Its totient is φ = 446260838400.
The previous prime is 1131402141197. The next prime is 1131402141203. The reversal of 1131402141200 is 21412041311.
It is an interprime number because it is at equal distance from previous prime (1131402141197) and next prime (1131402141203).
It can be written as a sum of positive squares in 18 ways, for example, as 511516761616 + 619885379584 = 715204^2 + 787328^2 .
It is a super-2 number, since 2×11314021412002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (1131402141203) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1960835312 + ... + 1960835888.
Almost surely, 21131402141200 is an apocalyptic number.
1131402141200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1131402141200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1378272932766).
1131402141200 is an abundant number, since it is smaller than the sum of its proper divisors (1625143724332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131402141200 is an equidigital number, since it uses as much as digits as its factorization.
1131402141200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1310 (or 1202 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 1131402141200 its reverse (21412041311), we get a palindrome (1152814182511).
The spelling of 1131402141200 in words is "one trillion, one hundred thirty-one billion, four hundred two million, one hundred forty-one thousand, two hundred".
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