Search a number
-
+
11314025561 is a prime number
BaseRepresentation
bin10101000100101111…
…00101010001011001
31002012111100001022202
422202113211101121
5141132342304221
65110402455545
7550241426156
oct124227452131
932174301282
1011314025561
114886521953
1222390645b5
1310b3cc63a7
1479489522d
1546341dd0b
hex2a25e5459

11314025561 has 2 divisors, whose sum is σ = 11314025562. Its totient is φ = 11314025560.

The previous prime is 11314025557. The next prime is 11314025579. The reversal of 11314025561 is 16552041311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10651272025 + 662753536 = 103205^2 + 25744^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314025561 - 22 = 11314025557 is a prime.

It is a super-2 number, since 2×113140255612 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11314025531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657012780 + 5657012781.

It is an arithmetic number, because the mean of its divisors is an integer number (5657012781).

Almost surely, 211314025561 is an apocalyptic number.

It is an amenable number.

11314025561 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314025561 is an equidigital number, since it uses as much as digits as its factorization.

11314025561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 11314025561 its reverse (16552041311), we get a palindrome (27866066872).

The spelling of 11314025561 in words is "eleven billion, three hundred fourteen million, twenty-five thousand, five hundred sixty-one".