Base | Representation |
---|---|
bin | 10101000100101111… |
… | …00101010001011001 |
3 | 1002012111100001022202 |
4 | 22202113211101121 |
5 | 141132342304221 |
6 | 5110402455545 |
7 | 550241426156 |
oct | 124227452131 |
9 | 32174301282 |
10 | 11314025561 |
11 | 4886521953 |
12 | 22390645b5 |
13 | 10b3cc63a7 |
14 | 79489522d |
15 | 46341dd0b |
hex | 2a25e5459 |
11314025561 has 2 divisors, whose sum is σ = 11314025562. Its totient is φ = 11314025560.
The previous prime is 11314025557. The next prime is 11314025579. The reversal of 11314025561 is 16552041311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10651272025 + 662753536 = 103205^2 + 25744^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314025561 - 22 = 11314025557 is a prime.
It is a super-2 number, since 2×113140255612 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11314025531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657012780 + 5657012781.
It is an arithmetic number, because the mean of its divisors is an integer number (5657012781).
Almost surely, 211314025561 is an apocalyptic number.
It is an amenable number.
11314025561 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314025561 is an equidigital number, since it uses as much as digits as its factorization.
11314025561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 11314025561 its reverse (16552041311), we get a palindrome (27866066872).
The spelling of 11314025561 in words is "eleven billion, three hundred fourteen million, twenty-five thousand, five hundred sixty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •