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113140444234 = 256570222117
BaseRepresentation
bin110100101011110110…
…0100010110001001010
3101211000221201001222111
41221113230202301022
53323202423203414
6123550452212534
711113503623356
oct1512754426112
9354027631874
10113140444234
1143a89916374
1219b1660a14a
13a891015a2c
145694308466
152e22b7e8c4
hex1a57b22c4a

113140444234 has 4 divisors (see below), whose sum is σ = 169710666354. Its totient is φ = 56570222116.

The previous prime is 113140444213. The next prime is 113140444247. The reversal of 113140444234 is 432444041311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 87234576025 + 25905868209 = 295355^2 + 160953^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113140444196 and 113140444205.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28285111057 + ... + 28285111060.

Almost surely, 2113140444234 is an apocalyptic number.

113140444234 is a deficient number, since it is larger than the sum of its proper divisors (56570222120).

113140444234 is an equidigital number, since it uses as much as digits as its factorization.

113140444234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56570222119.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 113140444234 its reverse (432444041311), we get a palindrome (545584485545).

The spelling of 113140444234 in words is "one hundred thirteen billion, one hundred forty million, four hundred forty-four thousand, two hundred thirty-four".

Divisors: 1 2 56570222117 113140444234