Base | Representation |
---|---|
bin | 110100101011110110… |
… | …0100010110001001010 |
3 | 101211000221201001222111 |
4 | 1221113230202301022 |
5 | 3323202423203414 |
6 | 123550452212534 |
7 | 11113503623356 |
oct | 1512754426112 |
9 | 354027631874 |
10 | 113140444234 |
11 | 43a89916374 |
12 | 19b1660a14a |
13 | a891015a2c |
14 | 5694308466 |
15 | 2e22b7e8c4 |
hex | 1a57b22c4a |
113140444234 has 4 divisors (see below), whose sum is σ = 169710666354. Its totient is φ = 56570222116.
The previous prime is 113140444213. The next prime is 113140444247. The reversal of 113140444234 is 432444041311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 87234576025 + 25905868209 = 295355^2 + 160953^2 .
It is a junction number, because it is equal to n+sod(n) for n = 113140444196 and 113140444205.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28285111057 + ... + 28285111060.
Almost surely, 2113140444234 is an apocalyptic number.
113140444234 is a deficient number, since it is larger than the sum of its proper divisors (56570222120).
113140444234 is an equidigital number, since it uses as much as digits as its factorization.
113140444234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56570222119.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 113140444234 its reverse (432444041311), we get a palindrome (545584485545).
The spelling of 113140444234 in words is "one hundred thirteen billion, one hundred forty million, four hundred forty-four thousand, two hundred thirty-four".
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