Base | Representation |
---|---|
bin | 1010010010100100001010… |
… | …1011000010101111010010 |
3 | 1111001121120110112112112202 |
4 | 2210221002223002233102 |
5 | 2440332144440443310 |
6 | 40021335235323202 |
7 | 2245262004642362 |
oct | 244510253025722 |
9 | 44047513475482 |
10 | 11314062437330 |
11 | 36722a331a544 |
12 | 13288a8750502 |
13 | 640bb0782ca3 |
14 | 2b18641a49a2 |
15 | 1494886d13a5 |
hex | a4a42ac2bd2 |
11314062437330 has 16 divisors (see below), whose sum is σ = 20366715314880. Its totient is φ = 4525313213232.
The previous prime is 11314062437263. The next prime is 11314062437341. The reversal of 11314062437330 is 3373426041311.
It is a super-3 number, since 3×113140624373303 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38817764 + ... + 39108143.
It is an arithmetic number, because the mean of its divisors is an integer number (1272919707180).
Almost surely, 211314062437330 is an apocalyptic number.
11314062437330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11314062437330 is a deficient number, since it is larger than the sum of its proper divisors (9052652877550).
11314062437330 is a wasteful number, since it uses less digits than its factorization.
11314062437330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77940433.
The product of its (nonzero) digits is 108864, while the sum is 38.
Adding to 11314062437330 its reverse (3373426041311), we get a palindrome (14687488478641).
The spelling of 11314062437330 in words is "eleven trillion, three hundred fourteen billion, sixty-two million, four hundred thirty-seven thousand, three hundred thirty".
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