Base | Representation |
---|---|
bin | 10101000100101111… |
… | …11111010001011001 |
3 | 1002012111112110102001 |
4 | 22202113333101121 |
5 | 141132404211212 |
6 | 5110405041001 |
7 | 550242351514 |
oct | 124227772131 |
9 | 32174473361 |
10 | 11314132057 |
11 | 4886594968 |
12 | 22390b6161 |
13 | 10b40329c7 |
14 | 7948c1d7b |
15 | 463440657 |
hex | 2a25ff459 |
11314132057 has 2 divisors, whose sum is σ = 11314132058. Its totient is φ = 11314132056.
The previous prime is 11314132003. The next prime is 11314132121. The reversal of 11314132057 is 75023141311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11145236041 + 168896016 = 105571^2 + 12996^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314132057 - 215 = 11314099289 is a prime.
It is not a weakly prime, because it can be changed into another prime (11314132157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657066028 + 5657066029.
It is an arithmetic number, because the mean of its divisors is an integer number (5657066029).
Almost surely, 211314132057 is an apocalyptic number.
It is an amenable number.
11314132057 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314132057 is an equidigital number, since it uses as much as digits as its factorization.
11314132057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 11314132057 its reverse (75023141311), we get a palindrome (86337273368).
The spelling of 11314132057 in words is "eleven billion, three hundred fourteen million, one hundred thirty-two thousand, fifty-seven".
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