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113141430331 is a prime number
BaseRepresentation
bin110100101011111000…
…0010011100000111011
3101211001000120011122121
41221113300103200323
53323203201232311
6123550525302111
711113515201316
oct1512760234073
9354030504577
10113141430331
1143a8a42a226
1219b16a04937
13a89129c817
1456944c397d
152e22cc6b71
hex1a57c1383b

113141430331 has 2 divisors, whose sum is σ = 113141430332. Its totient is φ = 113141430330.

The previous prime is 113141430319. The next prime is 113141430359. The reversal of 113141430331 is 133034141311.

It is a weak prime.

It is an emirp because it is prime and its reverse (133034141311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113141430331 - 27 = 113141430203 is a prime.

It is a super-2 number, since 2×1131414303312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113141430296 and 113141430305.

It is not a weakly prime, because it can be changed into another prime (113141430361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570715165 + 56570715166.

It is an arithmetic number, because the mean of its divisors is an integer number (56570715166).

Almost surely, 2113141430331 is an apocalyptic number.

113141430331 is a deficient number, since it is larger than the sum of its proper divisors (1).

113141430331 is an equidigital number, since it uses as much as digits as its factorization.

113141430331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 113141430331 its reverse (133034141311), we get a palindrome (246175571642).

The spelling of 113141430331 in words is "one hundred thirteen billion, one hundred forty-one million, four hundred thirty thousand, three hundred thirty-one".