Base | Representation |
---|---|
bin | 10000011101101101111… |
… | …110001111110101110010 |
3 | 11000011101201000221220000 |
4 | 100131231332033311302 |
5 | 122014122341330302 |
6 | 2223433503530430 |
7 | 144512451334344 |
oct | 20355576176562 |
9 | 4004351027800 |
10 | 1131421433202 |
11 | 3a69189a2905 |
12 | 16333a8b9a16 |
13 | 829007b46b8 |
14 | 3ca92603294 |
15 | 1e66e2a531c |
hex | 1076df8fd72 |
1131421433202 has 40 divisors (see below), whose sum is σ = 2558915804016. Its totient is φ = 373615794648.
The previous prime is 1131421433141. The next prime is 1131421433213. The reversal of 1131421433202 is 2023341241311.
1131421433202 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 4 + 21 + 433 + 202 = 666.
It is a super-3 number, since 3×11314214332023 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 32618568 + ... + 32653235.
Almost surely, 21131421433202 is an apocalyptic number.
1131421433202 is an abundant number, since it is smaller than the sum of its proper divisors (1427494370814).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131421433202 is a wasteful number, since it uses less digits than its factorization.
1131421433202 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65271924 (or 65271915 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 1131421433202 its reverse (2023341241311), we get a palindrome (3154762674513).
The spelling of 1131421433202 in words is "one trillion, one hundred thirty-one billion, four hundred twenty-one million, four hundred thirty-three thousand, two hundred two".
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