1131421433203 has 4 divisors (see below), whose sum is σ = 1132402719208. Its totient is φ = 1130440147200.

The previous prime is 1131421433141. The next prime is 1131421433213. The reversal of 1131421433203 is 3023341241311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1131421433203 - 2²¹ = 1131419336051 is a prime.

It is a super-2 number, since 2×1131421433203² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1131421433213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 490641273 + ... + 490643578.

It is an arithmetic number, because the mean of its divisors is an integer number (283100679802).

Almost surely, 2^{1131421433203} is an apocalyptic number.

1131421433203 is a deficient number, since it is larger than the sum of its proper divisors (981286005).

1131421433203 is an equidigital number, since it uses as much as digits as its factorization.

1131421433203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 981286004.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1131421433203 its reverse (3023341241311), we get a palindrome (4154762674514).

The spelling of 1131421433203 in words is "one trillion, one hundred thirty-one billion, four hundred twenty-one million, four hundred thirty-three thousand, two hundred three".