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113142212641555 = 597379615522197
BaseRepresentation
bin11001101110011011111001…
…011001001100001100010011
3112211121021211022222202220121
4121232123321121030030103
5104312210222414012210
61040344452005451111
732555153334343156
oct3156337131141423
9484537738882817
10113142212641555
1133061385474399
1210833876110a97
134b19359bcc9b6
141dd2180273c9d
15d1314e0406da
hex66e6f964c313

113142212641555 has 16 divisors (see below), whose sum is σ = 137532279921120. Its totient is φ = 89344277793792.

The previous prime is 113142212641529. The next prime is 113142212641583. The reversal of 113142212641555 is 555146212241311.

It is a cyclic number.

It is not a de Polignac number, because 113142212641555 - 27 = 113142212641427 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 307577284 + ... + 307944913.

It is an arithmetic number, because the mean of its divisors is an integer number (8595767495070).

Almost surely, 2113142212641555 is an apocalyptic number.

113142212641555 is a deficient number, since it is larger than the sum of its proper divisors (24390067279565).

113142212641555 is an equidigital number, since it uses as much as digits as its factorization.

113142212641555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 615522678.

The product of its digits is 288000, while the sum is 43.

Adding to 113142212641555 its reverse (555146212241311), we get a palindrome (668288424882866).

The spelling of 113142212641555 in words is "one hundred thirteen trillion, one hundred forty-two billion, two hundred twelve million, six hundred forty-one thousand, five hundred fifty-five".

Divisors: 1 5 97 379 485 1895 36763 183815 615522197 3077610985 59705653109 233282912663 298528265545 1166414563315 22628442528311 113142212641555