Base | Representation |
---|---|
bin | 11001101110011011111001… |
… | …011001001100001100010011 |
3 | 112211121021211022222202220121 |
4 | 121232123321121030030103 |
5 | 104312210222414012210 |
6 | 1040344452005451111 |
7 | 32555153334343156 |
oct | 3156337131141423 |
9 | 484537738882817 |
10 | 113142212641555 |
11 | 33061385474399 |
12 | 10833876110a97 |
13 | 4b19359bcc9b6 |
14 | 1dd2180273c9d |
15 | d1314e0406da |
hex | 66e6f964c313 |
113142212641555 has 16 divisors (see below), whose sum is σ = 137532279921120. Its totient is φ = 89344277793792.
The previous prime is 113142212641529. The next prime is 113142212641583. The reversal of 113142212641555 is 555146212241311.
It is a cyclic number.
It is not a de Polignac number, because 113142212641555 - 27 = 113142212641427 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 307577284 + ... + 307944913.
It is an arithmetic number, because the mean of its divisors is an integer number (8595767495070).
Almost surely, 2113142212641555 is an apocalyptic number.
113142212641555 is a deficient number, since it is larger than the sum of its proper divisors (24390067279565).
113142212641555 is an equidigital number, since it uses as much as digits as its factorization.
113142212641555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 615522678.
The product of its digits is 288000, while the sum is 43.
Adding to 113142212641555 its reverse (555146212241311), we get a palindrome (668288424882866).
The spelling of 113142212641555 in words is "one hundred thirteen trillion, one hundred forty-two billion, two hundred twelve million, six hundred forty-one thousand, five hundred fifty-five".
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