Base | Representation |
---|---|
bin | 10101000100110000… |
… | …10101110001110001 |
3 | 1002012111201010212021 |
4 | 22202120111301301 |
5 | 141132420133431 |
6 | 5110411031441 |
7 | 550243214335 |
oct | 124230256161 |
9 | 32174633767 |
10 | 11314224241 |
11 | 4886648151 |
12 | 223913b581 |
13 | 10b4065958 |
14 | 7949077c5 |
15 | 46345cb11 |
hex | 2a2615c71 |
11314224241 has 4 divisors (see below), whose sum is σ = 11473579584. Its totient is φ = 11154868900.
The previous prime is 11314224221. The next prime is 11314224263. The reversal of 11314224241 is 14242241311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14242241311 = 104597 ⋅136163.
It is a cyclic number.
It is not a de Polignac number, because 11314224241 - 225 = 11280669809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11314224221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79677565 + ... + 79677706.
It is an arithmetic number, because the mean of its divisors is an integer number (2868394896).
Almost surely, 211314224241 is an apocalyptic number.
It is an amenable number.
11314224241 is a deficient number, since it is larger than the sum of its proper divisors (159355343).
11314224241 is an equidigital number, since it uses as much as digits as its factorization.
11314224241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159355342.
The product of its digits is 1536, while the sum is 25.
Adding to 11314224241 its reverse (14242241311), we get a palindrome (25556465552).
The spelling of 11314224241 in words is "eleven billion, three hundred fourteen million, two hundred twenty-four thousand, two hundred forty-one".
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