Base | Representation |
---|---|
bin | 10101000100110000… |
… | …11010011000011001 |
3 | 1002012111202002201122 |
4 | 22202120122120121 |
5 | 141132421234342 |
6 | 5110411255025 |
7 | 550243323323 |
oct | 124230323031 |
9 | 32174662648 |
10 | 11314243097 |
11 | 4886660333 |
12 | 223914a475 |
13 | 10b4071401 |
14 | 794910613 |
15 | 4634634d2 |
hex | 2a261a619 |
11314243097 has 2 divisors, whose sum is σ = 11314243098. Its totient is φ = 11314243096.
The previous prime is 11314243091. The next prime is 11314243207. The reversal of 11314243097 is 79034241311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9488902921 + 1825340176 = 97411^2 + 42724^2 .
It is an emirp because it is prime and its reverse (79034241311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11314243097 - 24 = 11314243081 is a prime.
It is not a weakly prime, because it can be changed into another prime (11314243091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657121548 + 5657121549.
It is an arithmetic number, because the mean of its divisors is an integer number (5657121549).
Almost surely, 211314243097 is an apocalyptic number.
It is an amenable number.
11314243097 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314243097 is an equidigital number, since it uses as much as digits as its factorization.
11314243097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 11314243097 in words is "eleven billion, three hundred fourteen million, two hundred forty-three thousand, ninety-seven".
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