113143104421051 has 4 divisors (see below), whose sum is σ = 113146733043504. Its totient is φ = 113139475798600.

The previous prime is 113143104421031. The next prime is 113143104421093. The reversal of 113143104421051 is 150124401341311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113143104421051 - 2⁷ = 113143104420923 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113143104421031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1814264455 + ... + 1814326816.

It is an arithmetic number, because the mean of its divisors is an integer number (28286683260876).

Almost surely, 2^{113143104421051} is an apocalyptic number.

113143104421051 is a deficient number, since it is larger than the sum of its proper divisors (3628622453).

113143104421051 is an equidigital number, since it uses as much as digits as its factorization.

113143104421051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3628622452.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 113143104421051 its reverse (150124401341311), we get a palindrome (263267505762362).

The spelling of 113143104421051 in words is "one hundred thirteen trillion, one hundred forty-three billion, one hundred four million, four hundred twenty-one thousand, fifty-one".