Base | Representation |
---|---|
bin | 1010010010100101011011… |
… | …1110101100101101111011 |
3 | 1111001122110012121201222012 |
4 | 2210221112332230231323 |
5 | 2440333344200244311 |
6 | 40021433125520135 |
7 | 2245303312552163 |
oct | 244512676545573 |
9 | 44048405551865 |
10 | 11314403134331 |
11 | 3672458670210 |
12 | 132898287304b |
13 | 640c3622c94b |
14 | 2b189752d5a3 |
15 | 1494a857d78b |
hex | a4a56facb7b |
11314403134331 has 16 divisors (see below), whose sum is σ = 12402920724480. Its totient is φ = 10235956893120.
The previous prime is 11314403134303. The next prime is 11314403134373. The reversal of 11314403134331 is 13343130441311.
It is a cyclic number.
It is not a de Polignac number, because 11314403134331 - 218 = 11314402872187 is a prime.
It is a super-2 number, since 2×113144031343312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11314403154331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 705110 + ... + 4808948.
It is an arithmetic number, because the mean of its divisors is an integer number (775182545280).
Almost surely, 211314403134331 is an apocalyptic number.
11314403134331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11314403134331 is a deficient number, since it is larger than the sum of its proper divisors (1088517590149).
11314403134331 is a wasteful number, since it uses less digits than its factorization.
11314403134331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4105066.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 11314403134331 its reverse (13343130441311), we get a palindrome (24657533575642).
The spelling of 11314403134331 in words is "eleven trillion, three hundred fourteen billion, four hundred three million, one hundred thirty-four thousand, three hundred thirty-one".
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