Base | Representation |
---|---|
bin | 110100101011111101… |
… | …1110011000101101001 |
3 | 101211001020020020120212 |
4 | 1221113323303011221 |
5 | 3323204434140431 |
6 | 123551114030505 |
7 | 11113552620314 |
oct | 1512773630551 |
9 | 354036206525 |
10 | 113144443241 |
11 | 43a910a7935 |
12 | 19b17a18435 |
13 | a891ab5ccb |
14 | 5694a6997b |
15 | 2e231be72b |
hex | 1a57ef3169 |
113144443241 has 2 divisors, whose sum is σ = 113144443242. Its totient is φ = 113144443240.
The previous prime is 113144443207. The next prime is 113144443261. The reversal of 113144443241 is 142344441311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62185895641 + 50958547600 = 249371^2 + 225740^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113144443241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113144443198 and 113144443207.
It is not a weakly prime, because it can be changed into another prime (113144443261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56572221620 + 56572221621.
It is an arithmetic number, because the mean of its divisors is an integer number (56572221621).
Almost surely, 2113144443241 is an apocalyptic number.
It is an amenable number.
113144443241 is a deficient number, since it is larger than the sum of its proper divisors (1).
113144443241 is an equidigital number, since it uses as much as digits as its factorization.
113144443241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18432, while the sum is 32.
Adding to 113144443241 its reverse (142344441311), we get a palindrome (255488884552).
The spelling of 113144443241 in words is "one hundred thirteen billion, one hundred forty-four million, four hundred forty-three thousand, two hundred forty-one".
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