Base | Representation |
---|---|
bin | 110100101011111111… |
… | …1100101001111111011 |
3 | 101211001022002122012112 |
4 | 1221113333211033323 |
5 | 3323210212411011 |
6 | 123551151202535 |
7 | 11113564221161 |
oct | 1512777451773 |
9 | 354038078175 |
10 | 113145435131 |
11 | 43a91715083 |
12 | 19b1821644b |
13 | a892072621 |
14 | 5694c47231 |
15 | 2e2331858b |
hex | 1a57fe53fb |
113145435131 has 2 divisors, whose sum is σ = 113145435132. Its totient is φ = 113145435130.
The previous prime is 113145435097. The next prime is 113145435149. The reversal of 113145435131 is 131534541311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113145435131 is a prime.
It is a super-2 number, since 2×1131454351312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113145435031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56572717565 + 56572717566.
It is an arithmetic number, because the mean of its divisors is an integer number (56572717566).
Almost surely, 2113145435131 is an apocalyptic number.
113145435131 is a deficient number, since it is larger than the sum of its proper divisors (1).
113145435131 is an equidigital number, since it uses as much as digits as its factorization.
113145435131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10800, while the sum is 32.
Adding to 113145435131 its reverse (131534541311), we get a palindrome (244679976442).
It can be divided in two parts, 11314 and 5435131, that added together give a palindrome (5446445).
The spelling of 113145435131 in words is "one hundred thirteen billion, one hundred forty-five million, four hundred thirty-five thousand, one hundred thirty-one".
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