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11314730287481 is a prime number
BaseRepresentation
bin1010010010100110101001…
…1110101100000101111001
31111001200022000012211201112
42210221222132230011321
52440340031423144411
640021525413530105
72245314364402355
oct244515236540571
944050260184645
1011314730287481
113672606300215
121328a54343935
13640c88c469aa
142b18c8b70465
151494c7152b8b
hexa4a6a7ac179

11314730287481 has 2 divisors, whose sum is σ = 11314730287482. Its totient is φ = 11314730287480.

The previous prime is 11314730287463. The next prime is 11314730287493. The reversal of 11314730287481 is 18478203741311.

11314730287481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7139001515881 + 4175728771600 = 2671891^2 + 2043460^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314730287481 - 242 = 6916683776377 is a prime.

It is a super-2 number, since 2×113147302874812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11314730287381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657365143740 + 5657365143741.

It is an arithmetic number, because the mean of its divisors is an integer number (5657365143741).

Almost surely, 211314730287481 is an apocalyptic number.

It is an amenable number.

11314730287481 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314730287481 is an equidigital number, since it uses as much as digits as its factorization.

11314730287481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 903168, while the sum is 50.

The spelling of 11314730287481 in words is "eleven trillion, three hundred fourteen billion, seven hundred thirty million, two hundred eighty-seven thousand, four hundred eighty-one".