113148394673 has 4 divisors (see below), whose sum is σ = 119103573360. Its totient is φ = 107193215988.

The previous prime is 113148394669. The next prime is 113148394687. The reversal of 113148394673 is 376493841311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 376493841311 = 7 ⋅53784834473.

It is a cyclic number.

It is not a de Polignac number, because 113148394673 - 2² = 113148394669 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113148394613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2977589315 + ... + 2977589352.

It is an arithmetic number, because the mean of its divisors is an integer number (29775893340).

Almost surely, 2^113148394673 is an apocalyptic number.

It is an amenable number.

113148394673 is a deficient number, since it is larger than the sum of its proper divisors (5955178687).

113148394673 is an equidigital number, since it uses as much as digits as its factorization.

113148394673 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5955178686.

The product of its digits is 1306368, while the sum is 50.

The spelling of 113148394673 in words is "one hundred thirteen billion, one hundred forty-eight million, three hundred ninety-four thousand, six hundred seventy-three".