Base | Representation |
---|---|
bin | 110100101100001010… |
… | …1000000111001101001 |
3 | 101211001200200002001012 |
4 | 1221120111000321221 |
5 | 3323213132202132 |
6 | 123551511433305 |
7 | 11113663041053 |
oct | 1513025007151 |
9 | 354050602035 |
10 | 113151053417 |
11 | 43a94902196 |
12 | 19b1a085835 |
13 | a89328b95c |
14 | 56958aa8d3 |
15 | 2e23a780b2 |
hex | 1a58540e69 |
113151053417 has 2 divisors, whose sum is σ = 113151053418. Its totient is φ = 113151053416.
The previous prime is 113151053413. The next prime is 113151053447. The reversal of 113151053417 is 714350151311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107528903056 + 5622150361 = 327916^2 + 74981^2 .
It is a cyclic number.
It is not a de Polignac number, because 113151053417 - 22 = 113151053413 is a prime.
It is not a weakly prime, because it can be changed into another prime (113151053413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56575526708 + 56575526709.
It is an arithmetic number, because the mean of its divisors is an integer number (56575526709).
Almost surely, 2113151053417 is an apocalyptic number.
It is an amenable number.
113151053417 is a deficient number, since it is larger than the sum of its proper divisors (1).
113151053417 is an equidigital number, since it uses as much as digits as its factorization.
113151053417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 32.
The spelling of 113151053417 in words is "one hundred thirteen billion, one hundred fifty-one million, fifty-three thousand, four hundred seventeen".
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