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113200103131 = 557203231783
BaseRepresentation
bin110100101101101000…
…0000111111011011011
3101211012002222001121021
41221123100013323123
53323313211300011
6124000423023311
711115130000123
oct1513320077333
9354162861537
10113200103131
114400a563a45
1219b3259ab37
13a8a04a365b
14569c1d7c83
152e28016471
hex1a5b407edb

113200103131 has 4 divisors (see below), whose sum is σ = 113403335472. Its totient is φ = 112996870792.

The previous prime is 113200103129. The next prime is 113200103153. The reversal of 113200103131 is 131301002311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113200103131 - 21 = 113200103129 is a prime.

It is a super-2 number, since 2×1132001031312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113200103111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101615335 + ... + 101616448.

It is an arithmetic number, because the mean of its divisors is an integer number (28350833868).

Almost surely, 2113200103131 is an apocalyptic number.

113200103131 is a deficient number, since it is larger than the sum of its proper divisors (203232341).

113200103131 is an equidigital number, since it uses as much as digits as its factorization.

113200103131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203232340.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 113200103131 its reverse (131301002311), we get a palindrome (244501105442).

The spelling of 113200103131 in words is "one hundred thirteen billion, two hundred million, one hundred three thousand, one hundred thirty-one".

Divisors: 1 557 203231783 113200103131