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11320013312332 = 2211712416740673
BaseRepresentation
bin1010010010111010010101…
…0111110101000101001100
31111002011221012011022101121
42210232211113311011030
52440431341401443312
640024201535250324
72245562324356234
oct244564527650514
944064835138347
1011320013312332
113674877447a5a
121329a896799a4
1364161b60b9ba
142b1c6a666cc4
151496d5d63707
hexa4ba55f514c

11320013312332 has 12 divisors (see below), whose sum is σ = 19826940489496. Its totient is φ = 5655173172480.

The previous prime is 11320013312261. The next prime is 11320013312339. The reversal of 11320013312332 is 23321331002311.

11320013312332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11320013312297 and 11320013312306.

It is not an unprimeable number, because it can be changed into a prime (11320013312339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1208365653 + ... + 1208375020.

Almost surely, 211320013312332 is an apocalyptic number.

It is an amenable number.

11320013312332 is a deficient number, since it is larger than the sum of its proper divisors (8506927177164).

11320013312332 is a wasteful number, since it uses less digits than its factorization.

11320013312332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2416741848 (or 2416741846 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11320013312332 its reverse (23321331002311), we get a palindrome (34641344314643).

The spelling of 11320013312332 in words is "eleven trillion, three hundred twenty billion, thirteen million, three hundred twelve thousand, three hundred thirty-two".

Divisors: 1 2 4 1171 2342 4684 2416740673 4833481346 9666962692 2830003328083 5660006656166 11320013312332