Base | Representation |
---|---|
bin | 1010010010111010011100… |
… | …0011000001101100011001 |
3 | 1111002012000011000222210221 |
4 | 2210232213003001230121 |
5 | 2440431421100212101 |
6 | 40024204421440041 |
7 | 2245563115255450 |
oct | 244564703015431 |
9 | 44065004028727 |
10 | 11320041413401 |
11 | 36748912a0786 |
12 | 1329a96b70021 |
13 | 64162439a556 |
14 | 2b1c7029db97 |
15 | 1496d8564aa1 |
hex | a4ba70c1b19 |
11320041413401 has 16 divisors (see below), whose sum is σ = 13067599888000. Its totient is φ = 9605485398528.
The previous prime is 11320041413389. The next prime is 11320041413407. The reversal of 11320041413401 is 10431414002311.
It is a cyclic number.
It is not a de Polignac number, because 11320041413401 - 225 = 11320007858969 is a prime.
It is a super-2 number, since 2×113200414134012 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11320041413407) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16328280 + ... + 17007433.
It is an arithmetic number, because the mean of its divisors is an integer number (816724993000).
Almost surely, 211320041413401 is an apocalyptic number.
It is an amenable number.
11320041413401 is a deficient number, since it is larger than the sum of its proper divisors (1747558474599).
11320041413401 is a wasteful number, since it uses less digits than its factorization.
11320041413401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33336208.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 11320041413401 its reverse (10431414002311), we get a palindrome (21751455415712).
The spelling of 11320041413401 in words is "eleven trillion, three hundred twenty billion, forty-one million, four hundred thirteen thousand, four hundred one".
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