Base | Representation |
---|---|
bin | 110100101101101001… |
… | …0010011000111011011 |
3 | 101211012011001000122112 |
4 | 1221123102103013123 |
5 | 3323313333020433 |
6 | 124000443142535 |
7 | 11115134563220 |
oct | 1513322230733 |
9 | 354164030575 |
10 | 113200673243 |
11 | 4400a913309 |
12 | 19b32814a4b |
13 | a8a0642cb8 |
14 | 569c305947 |
15 | 2e280ca348 |
hex | 1a5b4931db |
113200673243 has 4 divisors (see below), whose sum is σ = 129372198000. Its totient is φ = 97029148488.
The previous prime is 113200673231. The next prime is 113200673291. The reversal of 113200673243 is 342376002311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113200673243 - 210 = 113200672219 is a prime.
It is a super-2 number, since 2×1132006732432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113200673213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8085762368 + ... + 8085762381.
It is an arithmetic number, because the mean of its divisors is an integer number (32343049500).
Almost surely, 2113200673243 is an apocalyptic number.
113200673243 is a deficient number, since it is larger than the sum of its proper divisors (16171524757).
113200673243 is an equidigital number, since it uses as much as digits as its factorization.
113200673243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16171524756.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 113200673243 its reverse (342376002311), we get a palindrome (455576675554).
The spelling of 113200673243 in words is "one hundred thirteen billion, two hundred million, six hundred seventy-three thousand, two hundred forty-three".
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