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113201133113 = 432632584491
BaseRepresentation
bin110100101101101010…
…0000011011000111001
3101211012011220101110202
41221123110003120321
53323313442224423
6124000501051545
711115141520025
oct1513324033071
9354164811422
10113201133113
11440100a7872
1219b329b6bb5
13a8a0774403
14569c3c5385
152e2816b728
hex1a5b503639

113201133113 has 4 divisors (see below), whose sum is σ = 115833717648. Its totient is φ = 110568548580.

The previous prime is 113201133103. The next prime is 113201133137. The reversal of 113201133113 is 311331102311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113201133113 - 212 = 113201129017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113201133103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1316292203 + ... + 1316292288.

It is an arithmetic number, because the mean of its divisors is an integer number (28958429412).

Almost surely, 2113201133113 is an apocalyptic number.

It is an amenable number.

113201133113 is a deficient number, since it is larger than the sum of its proper divisors (2632584535).

113201133113 is an equidigital number, since it uses as much as digits as its factorization.

113201133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2632584534.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113201133113 its reverse (311331102311), we get a palindrome (424532235424).

The spelling of 113201133113 in words is "one hundred thirteen billion, two hundred one million, one hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 43 2632584491 113201133113