Base | Representation |
---|---|
bin | 110100101101101010… |
… | …0011000111011001001 |
3 | 101211012012001212110201 |
4 | 1221123110120323021 |
5 | 3323314003040241 |
6 | 124000503012201 |
7 | 11115142335136 |
oct | 1513324307311 |
9 | 354165055421 |
10 | 113201221321 |
11 | 44010158071 |
12 | 19b32a3a061 |
13 | a8a07a55c6 |
14 | 569c40958d |
15 | 2e28187931 |
hex | 1a5b518ec9 |
113201221321 has 2 divisors, whose sum is σ = 113201221322. Its totient is φ = 113201221320.
The previous prime is 113201221303. The next prime is 113201221337. The reversal of 113201221321 is 123122102311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112523348025 + 677873296 = 335445^2 + 26036^2 .
It is a cyclic number.
It is not a de Polignac number, because 113201221321 - 27 = 113201221193 is a prime.
It is not a weakly prime, because it can be changed into another prime (113201221421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600610660 + 56600610661.
It is an arithmetic number, because the mean of its divisors is an integer number (56600610661).
Almost surely, 2113201221321 is an apocalyptic number.
It is an amenable number.
113201221321 is a deficient number, since it is larger than the sum of its proper divisors (1).
113201221321 is an equidigital number, since it uses as much as digits as its factorization.
113201221321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 113201221321 its reverse (123122102311), we get a palindrome (236323323632).
The spelling of 113201221321 in words is "one hundred thirteen billion, two hundred one million, two hundred twenty-one thousand, three hundred twenty-one".
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