Base | Representation |
---|---|
bin | 1010010010111010101111… |
… | …1010010101111100010011 |
3 | 1111002012012211121012022020 |
4 | 2210232223322111330103 |
5 | 2440432102443214443 |
6 | 40024220454542523 |
7 | 2245565126034615 |
oct | 244565372257423 |
9 | 44065184535266 |
10 | 11320123023123 |
11 | 3674923371332 |
12 | 1329aba367a43 |
13 | 641638272525 |
14 | 2b1c7b064db5 |
15 | 1496e07d5583 |
hex | a4babe95f13 |
11320123023123 has 8 divisors (see below), whose sum is σ = 15096173064336. Its totient is φ = 7545410832000.
The previous prime is 11320123023107. The next prime is 11320123023199. The reversal of 11320123023123 is 32132032102311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11320123023123 - 24 = 11320123023107 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11320123023093 and 11320123023102.
It is not an unprimeable number, because it can be changed into a prime (11320123013123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 334442778 + ... + 334476623.
It is an arithmetic number, because the mean of its divisors is an integer number (1887021633042).
Almost surely, 211320123023123 is an apocalyptic number.
11320123023123 is a deficient number, since it is larger than the sum of its proper divisors (3776050041213).
11320123023123 is an equidigital number, since it uses as much as digits as its factorization.
11320123023123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 668925045.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 11320123023123 its reverse (32132032102311), we get a palindrome (43452155125434).
The spelling of 11320123023123 in words is "eleven trillion, three hundred twenty billion, one hundred twenty-three million, twenty-three thousand, one hundred twenty-three".
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