Search a number
-
+
113201231323 is a prime number
BaseRepresentation
bin110100101101101010…
…0011011010111011011
3101211012012002101012011
41221123110123113123
53323314003400243
6124000503130351
711115142406245
oct1513324332733
9354165071164
10113201231323
1144010164634
1219b32a439b7
13a8a07aa01b
14569c40d095
152e2818a89d
hex1a5b51b5db

113201231323 has 2 divisors, whose sum is σ = 113201231324. Its totient is φ = 113201231322.

The previous prime is 113201231287. The next prime is 113201231357. The reversal of 113201231323 is 323132102311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113201231323 - 213 = 113201223131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113201231294 and 113201231303.

It is not a weakly prime, because it can be changed into another prime (113201231383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600615661 + 56600615662.

It is an arithmetic number, because the mean of its divisors is an integer number (56600615662).

Almost surely, 2113201231323 is an apocalyptic number.

113201231323 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201231323 is an equidigital number, since it uses as much as digits as its factorization.

113201231323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 113201231323 its reverse (323132102311), we get a palindrome (436333333634).

The spelling of 113201231323 in words is "one hundred thirteen billion, two hundred one million, two hundred thirty-one thousand, three hundred twenty-three".